[lxc-users] LXC and Docker together?

Anton Chernousov chernousov at gita-dev.ru
Thu May 23 04:29:17 UTC 2019


About one year ago i'm tried to use Docker in LXD container with no 
results. Now i'm try to start it again and took this error:

root at docker:~# docker run hello-world
Unable to find image 'hello-world:latest' locally
latest: Pulling from library/hello-world
1b930d010525: Pull complete
Digest: 
sha256:0e11c388b664df8a27a901dce21eb89f11d8292f7fca1b3e3c4321bf7897bffe
Status: Downloaded newer image for hello-world:latest
docker: Error response from daemon: OCI runtime create failed: 
container_linux.go:345: starting container process caused 
"process_linux.go:424: container init caused \"rootfs_linux.go:58: 
mounting \\\"proc\\\" to rootfs 
\\\"/var/lib/docker/vfs/dir/6a8fe2649ebdd956657fc113a0e71ddb56ccfb145410dedd35ba8589bd0e1ffb\\\" 
at \\\"/proc\\\" caused \\\"permission denied\\\"\"": unknown.
ERRO[0005] error waiting for container: context canceled

As i can see it not working for now :(

==================================

With best regards, Anton Chernousov
Skype: live:chernousov.a
Telegram: @gitadev
Email: info at gita-dev.ru
Web: https://blog.gita-dev.ru
Phone: +7-(383)-202-14-78

23.05.2019 10:32, Richard Hector пишет:
> Hi all,
>
> I've been asked by my client to set up Docker on the host I'd set up for
> them with LXC (on Debian Stretch). This is because the applications that
> run in the containers (Atlassian suite, mostly) will in the future be
> managed by a different contractor, who is familiar with Docker. So
> eventually, I expect most or all of the LXC containers will be replaced
> with Docker ones.
>
> It appears that I can install Docker from the Docker repo, so that's ok.
>
> What I'm more worried about, is if they're both using the same
> underlying technology (are they?) whether they'll interact in bad and/or
> unexpected ways.
>
> Am I likely to be safe doing this? Anything to watch out for?
>
> And will I eventually be able to uninstall LXC without disrupting Docker?
>
> Thanks,
> Richard
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