[Lxc-users] [PATCH 9/9] lxc-destroy: wait until the container is stopped
Serge Hallyn
serge.hallyn at canonical.com
Mon May 28 03:07:43 UTC 2012
Quoting Daniel Lezcano (daniel.lezcano at free.fr):
> On 04/26/2012 07:09 AM, Serge Hallyn wrote:
> >From: Serge Hallyn<serge.hallyn at ubuntu.com>
> >
> >Author: Timothy Chen<tnachen at gmail.com>
> >Bug-Ubuntu: https://bugs.launchpad.net/ubuntu/+source/lxc/+bug/980902
> >
> >Signed-off-by: Serge Hallyn<serge.hallyn at ubuntu.com>
> >Cc: Timothy Chen<tnachen at gmail.com>
> >---
> > src/lxc/lxc-destroy.in | 1 +
> > 1 file changed, 1 insertion(+)
> >
> >diff --git a/src/lxc/lxc-destroy.in b/src/lxc/lxc-destroy.in
> >index b0f2da5..17fa6d6 100644
> >--- a/src/lxc/lxc-destroy.in
> >+++ b/src/lxc/lxc-destroy.in
> >@@ -87,6 +87,7 @@ lxc-info -n $lxc_name 2>/dev/null | grep -q RUNNING
> > if [ $? -eq 0 ]; then
> > if [ $force -eq 1 ]; then
> > lxc-stop -n $lxc_name
> >+ lxc-wait -n $lxc_name -s STOPPED
> > else
> > echo "Container $lxc_name is running, aborting the deletion."
> > exit 1
>
> I don't get why this is needed, lxc-stop is synchronous. When the
Actually I don't see where lxc-stop waits on anything. It sends the
sigkill, then sends a 'done' message back to the peer.
-serge
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