[Lxc-users] lxc-ubuntu: Base arch detection code on debootstrap's with some additions when we don't have dpkg or udpkg
Serge Hallyn
serge.hallyn at canonical.com
Thu Jun 23 16:19:32 UTC 2011
Quoting Stéphane Graber (stgraber at ubuntu.com):
>
> Signed-off-by: Stéphane Graber <stgraber at ubuntu.com>
> ---
> templates/lxc-ubuntu.in | 24 ++++++++++++++++++------
> 1 files changed, 18 insertions(+), 6 deletions(-)
>
> diff --git a/templates/lxc-ubuntu.in b/templates/lxc-ubuntu.in
> index 2a20c7d..4f75336 100644
> --- a/templates/lxc-ubuntu.in
> +++ b/templates/lxc-ubuntu.in
> @@ -391,15 +391,27 @@ eval set -- "$options"
>
> release=lucid
> bindhome=
> -arch=$(arch)
> -trim_container=0
> -if [ "$arch" == "x86_64" ]; then arch=amd64
> -fi
>
> -if [ "$arch" == "i386" ]; then
> - arch=i686
> +# Code taken from debootstrap
> +if [ "$arch" != "" ]; then
> + true
My only objection here is that I don't think we want to support passing
arch in through the environment. Now that we support passing it in through
command line, supporting environment as well seems a bit too magic.
What do you think?
The rest looks good, thanks.
> +elif [ -x /usr/bin/dpkg ] && /usr/bin/dpkg --print-architecture >/dev/null 2>&1; then
> + arch=`/usr/bin/dpkg --print-architecture`
> +elif type udpkg >/dev/null 2>&1 && udpkg --print-architecture >/dev/null 2>&1; then
> + arch=`/usr/bin/udpkg --print-architecture`
> +else
> + arch=$(arch)
> + if [ "$arch" = "i686" ]; then
> + arch="i386"
> + elif [ "$arch" = "x86_64" ]; then
> + arch="amd64"
> + elif [ "$arch" = "armv7l" ]; then
> + arch="armel"
> + fi
> fi
>
> +trim_container=0
> +
> hostarch=$arch
> while true
> do
> --
> 1.7.5.4
>
>
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