[lxc-devel] [PATCH v2] output lxc.arch as i686 for PER_LINUX32
Dwight Engen
dwight.engen at oracle.com
Mon Apr 28 20:51:06 UTC 2014
When outputing the lxc.arch setting, use i686 instead of x86 since the
later is not a valid input to setarch, nor will the kernel output
UTS_MACHINE as x86. The kernel sets utsname.machine to i[3456]86, which
all map to PER_LINUX32.
Signed-off-by: Dwight Engen <dwight.engen at oracle.com>
---
v2: use i686 instead of i386
src/lxc/confile.c | 4 ++--
1 file changed, 2 insertions(+), 2 deletions(-)
diff --git a/src/lxc/confile.c b/src/lxc/confile.c
index 4e7dead..04bd03c 100644
--- a/src/lxc/confile.c
+++ b/src/lxc/confile.c
@@ -1807,7 +1807,7 @@ static int lxc_get_arch_entry(struct lxc_conf *c, char *retv, int inlen)
int len = 0;
switch(c->personality) {
- case PER_LINUX32: strprint(retv, inlen, "x86"); break;
+ case PER_LINUX32: strprint(retv, inlen, "i686"); break;
case PER_LINUX: strprint(retv, inlen, "x86_64"); break;
default: break;
}
@@ -2259,7 +2259,7 @@ void write_config(FILE *fout, struct lxc_conf *c)
fprintf(fout, "lxc.stopsignal = SIG%s\n", sig_name(c->stopsignal));
#if HAVE_SYS_PERSONALITY_H
switch(c->personality) {
- case PER_LINUX32: fprintf(fout, "lxc.arch = x86\n"); break;
+ case PER_LINUX32: fprintf(fout, "lxc.arch = i686\n"); break;
case PER_LINUX: fprintf(fout, "lxc.arch = x86_64\n"); break;
default: break;
}
--
1.9.0
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