[lxc-devel] Two process on a same namespcae with clone()

[Maheswara Reddy C - ERS, HCL Tech]

Hi,

Fine,fork() always create new process, but here both the processes are different stacks.
If I use foek(), it will run the same instance of ABC_stack ,rather XYZ_stack.
Shall we call the clone() with out  CLONE_NEW* flags, so that it will run in the same name space.
See the below scenario, multiple namespaces each namespace has to run two different processes.

Main
{

 Ns1=Clone(CLONE_NEWNS)  ----> process1 (ABC_Stack)
                      |
.                     ---------->Process2 (XYZ_stack)
.


 Ns2=Clone(CLONE_NEWNS)  ----> process1 (ABC_Stack)
                      |
.                     ---------->Process2 (XYZ_stack)
.
.
.ns100clone(CLONE_NEWNS)


}



Thanks
Mahesh


-----Original Message-----
From: Rob Landley [mailto:rlandley at parallels.com]
Sent: Wednesday, February 16, 2011 7:10 PM
To: lxc-devel at lists.sourceforge.net; Maheswara Reddy C - ERS, HCL Tech
Subject: Re: [lxc-devel] Two process on a same namespcae with clone()

On 02/16/2011 01:25 AM, Maheswara Reddy C - ERS, HCL Tech wrote:
> Hi,
>
> Could someone help me out,
>
> I want to run the two process on same name space, shall it possible
> using the clone()

You call clone with the CLONE_NEW* flags to create a new namespace.  And
then you just fork() normally (without those flags) to create additional
processes in that same namespace.

It's a bit like chroot: you do something extra to get in it, and then
children inherit that environment by default.

Rob

P.S. Fix your hilarious legalese .sig.

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